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The general term is 1/(n-1)n(n+1).After playing with this a little, it looks like:1/(n-1)n(n+1) = (1/2) [1/(n-1)n - 1/n(n+1)]
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nth term=1/(n)(n+1)(n+2)
equate n+1=0
implies,n=-1
substitute in n+2
-1+2 =1
similarly
equate n+2=0
implies n=-2
substitute the value of n in n+1
=-2+1 =-1
man the answer doesnt seem right, if u enter n=1, the sum to n terms comes to be negative..
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