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`        10th term of the progression -4-1+2+5+--------------`
7 years ago

```							Dear jayku kumar,
The Formula for finding the nth term in Arithmetic Progression is given by
an = a1 + (n-1)d
where,
an is the value of the nth term
a1 is the value of the first term
n is the nth term
d is the difference

In this case, a1 = -4, d = (a2 -a1) = 3, n=10
Therefore substituting these values,we get the value of the nth term(an)
Therefore, an = -4 + (10-1)3
= -4 +(9)3
= -4+ 27
= 23
Hence the 10th term is 23.

Hope this helped you immensely...!!
All the Very Best & Good Luck to you ...!!

Best Regards,
Godfrey Classic Prince
IIT-M
Please approve my answer if you liked it by clicking on "Yes" given below..!! ```
7 years ago
```							Here, a=-4
and, d = -1-(-4) = 3
a10 = a+(n-1)d = -4+(10-1)(3) = -4+27 = 23.
Therefore, the 10th term is 23.
```
7 years ago
```							It is in A.P then a = -4 , d=3 then 10th term is  a+( n - 1 ) X d ,   - 4 + 9X 3 = -4 + 27 = 23
```
7 years ago
```							T=A+(n-1)d
A= -4 , n=10 , d= -1-(-4)=3
T=-4+(10-1)3= 23
```
7 years ago
```							23...
a=-4,
n=10,
d=-1+4=+3,
a=l+(n-1)d..therefore l=-4+27=23
```
7 years ago
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