Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
10th term of the progression -4-1+2+5+--------------
Dear jayku kumar,
The Formula for finding the nth term in Arithmetic Progression is given by
an = a1 + (n-1)d
where,
an is the value of the nth term
a1 is the value of the first term
n is the nth term
d is the difference
In this case, a1 = -4, d = (a2 -a1) = 3, n=10
Therefore substituting these values,we get the value of the nth term(an)
Therefore, an = -4 + (10-1)3
= -4 +(9)3
= -4+ 27
= 23
Hence the 10th term is 23.
Hope this helped you immensely...!!
All the Very Best & Good Luck to you ...!!
Best Regards,
AskIITians Expert,
Godfrey Classic Prince
IIT-M
Please approve my answer if you liked it by clicking on "Yes" given below..!!
Here, a=-4
and, d = -1-(-4) = 3
a10 = a+(n-1)d = -4+(10-1)(3) = -4+27 = 23.
Therefore, the 10th term is 23.
It is in A.P then a = -4 , d=3 then 10th term is a+( n - 1 ) X d , - 4 + 9X 3 = -4 + 27 = 23
T=A+(n-1)d
A= -4 , n=10 , d= -1-(-4)=3
T=-4+(10-1)3= 23
23...
a=-4,
n=10,
d=-1+4=+3,
a=l+(n-1)d..therefore l=-4+27=23
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !