 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        The sum of all natural numbers less than 200, that are divisible neither by 3 nor by 5 is
(1)10730
(2)15375
(3)10732
(4)none of these
Tell me the process.```
7 years ago

```							answer is "3"
first find the sum of  multiples of 3
that is  3+6+9+...........+198=Sn1=n(a+l)/2
we know that last term is 198 so "l"is 198 and a is 3 we have to find n value
we know that Tn =a+(n-1)d
198=3(n-1)3
n=66
there fore Sn1=66(3+198)/2  =6633
second find the sum of multiples of 5  similarly
we get Sn2=3900
then find the sum of multiples of 15  similarly because 15 is divisible by 3 and 5
so we get Sn3=1365
now add Sn1 and Sn2  then substract Sn3 from it
we get Sn=6633+3900-1365=9168
now we have to find sum to 199 with a=1 , d=1
we get S199=19900
now substract Sn from  S199
there fore the final answer is 19900-9168=10732
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions