Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

prove that- (x^6)+ (x^4) +(x^2)+x+3=0 has no real roots.

prove that-


(x^6)+ (x^4) +(x^2)+x+3=0


has no real roots.

Grade:11

4 Answers

Himanshu Sharma
31 Points
8 years ago

there are 2 negative roots..

Himanshu Sharma
31 Points
8 years ago

well this eqn has 2 negatice roots....question is wrong

Arpit Jaiswal
31 Points
8 years ago

thats incorrect!

Arpit Jaiswal
31 Points
8 years ago

this was simple enough and i figured it out-

all the termsof this equation are to be positive for any real number, because square of any real no. is positive, and the remaining x for sure will have a value which is smaller than (x^6)+(x^4)+(x^2) therefore to get 0, x has to be imaginary.

to get 0.

 

:D

AJ

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free