prove that- (x^6)+ (x^4) +(x^2)+x+3=0 has no real roots.

Question

Himanshu Sharma · Answer

there are 2 negative roots..

Himanshu Sharma · Answer

well this eqn has 2 negatice roots....question is wrong

Arpit Jaiswal · Answer

thats incorrect!

Arpit Jaiswal · Answer

this was simple enough and i figured it out-

all the termsof this equation are to be positive for any real number, because square of any real no. is positive, and the remaining x for sure will have a value which is smaller than (x^6)+(x^4)+(x^2) therefore to get 0, x has to be imaginary.

to get 0.

:D

AJ

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

prove that- (x^6)+ (x^4) +(x^2)+x+3=0 has no real roots.

prove that-

(x^6)+ (x^4) +(x^2)+x+3=0

has no real roots.

4 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Algebra

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship