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prove that- (x^6)+ (x^4) +(x^2)+x+3=0 has no real roots.

prove that-


(x^6)+ (x^4) +(x^2)+x+3=0


has no real roots.

Grade:11

4 Answers

Himanshu Sharma
31 Points
11 years ago

there are 2 negative roots..

Himanshu Sharma
31 Points
11 years ago

well this eqn has 2 negatice roots....question is wrong

Arpit Jaiswal
31 Points
11 years ago

thats incorrect!

Arpit Jaiswal
31 Points
11 years ago

this was simple enough and i figured it out-

all the termsof this equation are to be positive for any real number, because square of any real no. is positive, and the remaining x for sure will have a value which is smaller than (x^6)+(x^4)+(x^2) therefore to get 0, x has to be imaginary.

to get 0.

 

:D

AJ

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