Last Activity: 12 Years ago
We use the identity that
a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 + b^2 + c^2 - ab - bc - ca)
Now, if a+b+c = 0, the RHS becomes zero, thus the LHS is also zero
=> a^3 + b^3 + c^3 - 3abc = 0
=> a^3 + b^3 + c^3 = 3abc
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 10 Month ago(s)
Last Activity: 1 Year ago(s)
Last Activity: 2 Year ago(s)