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2/1! + 4/3! + 6/5! + . . . . . . . .=e
nth term of the series Tn=2n/(2n-1)!=(2n-1+1)/(2n-1)!=1/(2n-2)!+1/(2n-1)!putting n=1,2,3,...........T1=1/0!+1/1!T2=1/2!+1/3!T3=1/4!+1/5!...................................................Adding all these terms on both sides, we getT1+T2+T3+..............=1+1/1!+1/2!+1/3!+............=eThanks & RegardsRinkoo GuptaAskIITians Faculty
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