Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
2/1! + 4/3! + 6/5! + . . . . . . . .=e
nth term of the series Tn=2n/(2n-1)!=(2n-1+1)/(2n-1)!=1/(2n-2)!+1/(2n-1)!putting n=1,2,3,...........T1=1/0!+1/1!T2=1/2!+1/3!T3=1/4!+1/5!...................................................Adding all these terms on both sides, we getT1+T2+T3+..............=1+1/1!+1/2!+1/3!+............=eThanks & RegardsRinkoo GuptaAskIITians Faculty
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -