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g(x)=x-1/x f(g(x))=x^3-1/x^3 then prove that f(x)=3x^2+3
g(x)=x-1/x f(g(x))=x^3-1/x^3
then prove that f(x)=3x^2+3
f(g(x))=(x-1/x)3+3(x.1/x)(x-1/x) f(y) =y3+3y y=x-1/x
f(g(x))=(x-1/x)3+3(x.1/x)(x-1/x)
f(y) =y3+3y y=x-1/x
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