We know that if the discriminant of a quadratic equation is greater than zero & it is a perfect square then roots are real, distinct & rational. I was solving a question in which the quadratic equation had rational coefficients & when I found its discriminant, it was a perfect square but still I found that its roots are irrational...is it possible as I know that quadratic equations irrational roots & rational coefficients...always occur in conjugate pairs....BUT the problem was that my D was prect square & still roots were irrational. This is the question 2x 2 - 2 root 3x + 1

We know that if the discriminant of a quadratic equation is greater than zero & it is a perfect square then roots are real, distinct & rational. I was solving a question in which the quadratic equation had rational coefficients & when I found its discriminant, it was a perfect square but still I found that its roots are irrational...is it possible as I know that quadratic equations irrational roots & rational coefficients...always occur in conjugate pairs....BUT the problem was that my D was prect square & still roots were irrational. This is the question 2x²- 2 root 3x  + 1