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ultimate value of 'log[(1+d)(1+2d)(1+3d)...(1+nd)]'

preeti pooja , 13 Years ago

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Jitender Singh

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Hello Student,
Please find answer to your question

$A = log[(1+d)(1+2d)(1+3d)...............(1+nd)]$

$log(ab) = log(a) + log(b)$ $A = log(1+d) + log(1+2d) + log(1+3d) +............... + log(1+nd)$ $A = \sum_{r = 1}^{n}log(1+rd)$
$A = log(d^{n}(1+\frac{1}{d})_{n})$

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