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ultimate value of 'log[(1+d)(1+2d)(1+3d)...(1+nd)]'

preeti pooja , 13 Years ago
Grade
anser 1 Answers
Jitender Singh

Last Activity: 11 Years ago

Ans:
Hello Student,
Please find answer to your question

A = log[(1+d)(1+2d)(1+3d)...............(1+nd)]

log(ab) = log(a) + log(b)A = log(1+d) + log(1+2d) + log(1+3d) +............... + log(1+nd)A = \sum_{r = 1}^{n}log(1+rd)
A = log(d^{n}(1+\frac{1}{d})_{n})
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