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the num of terms in an AAAP is even;the sum of odd terms is 24,of the even terms is 30,and the last term exceeds the first term by 21/2,find the num of terms and the series the num of terms in an AAAP is even;the sum of odd terms is 24,of the even terms is 30,and the last term exceeds the first term by 21/2,find the num of terms and the series
the num of terms in an AAAP is even;the sum of odd terms is 24,of the even terms is 30,and the last term exceeds the first term by 21/2,find the num of terms and the series
Hello student,Please find the answer to your questionLet the total number of terms=2nAccording to the questionT1+T3+.......+T2n-1=24.......(1)T2+T4+...........+T2n=30.........(2)subtracting 2 from 1 we get(d+d+d+....)=6so nd=6T2n=T1+21/2T2n-a=21/2a+(2n-1)d-a=21/22nd-d=21/22(6)-d=21/2So d=3/2nd=6 so n=42n=8So number of terms=8T2+T4+...........+T2n=30(a+d)+(a+3d)+....+(a+(2n-1)d)=30by putting n=4,a=3/2 we get d=3/2So,the series will be 3/2,3,9/2,......
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