no of solutions of (6-x)^4 +(8-x)^4=32

Hello student,
Please find the answer to your question below
Given (6-x)^4 +(8-x)^4=32........(1)
Let y AM of 6-x and 8-x =7-x
so eqn(1) becomes (y+1)⁴+(y-1)⁴=32
on simplifying we get y⁴+6y²-15=0
let y²=u we get u²+6u-15=0
we get u=-32
so y=i,-i,-,
so x=7+,7-,7+,7-

Hence there are 4 solutions