(x2-x1)2+(3√8 +√(4-x12) - √(x22-16) )2
find its minimum value.
(x2-x1)2+(3√8 +√(4-x12) - √(x22-16) )2
find its minimum value.
kushal satya , 14 Years ago
Grade 10
Algebra> minimum value...
2 Answers
nukala viswateja
it has minimum value when x1=x2=4
minimum value=[4-4]2 +[3
|
√8+[4-4]]2+
|
kushal satya
THE SOLUTION IS WRONG SINCE
√(4-x12) IS NEGATIVE.
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