(x 2 -x 1 ) 2 +(3√8 +√(4-x 1 2 ) - √(x 2 2 -16) ) 2 find its minimum value.

Question

(x 2 -x 1 ) 2 +(3&radic;8 +&radic;(4-x 1 2 ) - &radic;(x 2 2 -16) ) 2 find its minimum value.

nukala viswateja · Answer

it has minimum value when x 1 =x 2 =4 minimum value=[4-4] 2 +[3 &radic;8+[4-4]] 2 + [&radic;16-16] 2 =9x8 =72

kushal satya · Answer

THE SOLUTION IS WRONG SINCE &radic;(4-x 1 2 ) IS NEGATIVE.

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(x 2 -x 1 ) 2 +(3√8 +√(4-x 1 2 ) - √(x 2 2 -16) ) 2 find its minimum value.

(x₂-x₁)²+(3√8 +√(4-x₁²) - √(x₂²-16) )²

find its minimum value.

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(x 2 -x 1 ) 2 +(3√8 +√(4-x 1 2 ) - √(x 2 2 -16) ) 2 find its minimum value.

(x2-x1)2+(3√8 +√(4-x12) - √(x22-16) )2 find its minimum value.

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(x₂-x₁)²+(3√8 +√(4-x₁²) - √(x₂²-16) )²

find its minimum value.