let a,b,c, be roots of x^3+x^2-5x-1=0 then [a]+[b]+[c] =1)1 2)2 3)-2 4)-3

 in this question find f(-3) ,f(-2),f(-1),f(0),f(1),f(2) you will find that f(1)f(2)<0, f(-1)f(0)<0 , f(-3)f(-2)<0 this implie the three roots lies between (-3,-2) , (-1,0) , (1,2)

so [a]+[b]+[c] = -3-1+1 = -3

Ans is 4) -3

Approved