If a+b+c=0=p+q+r then the value of determinant paqb rc qcrapbrb pc qais? how

When we open the matrice we get

              prq(a³ + b³ + c³) - abc(p³ + q³ +r³)

    we have a+b+c = p+q+r =0

     so a³+b³+c³ = 3abc    and     p³+r³+q³ = 3pqr

     putting values in above equation we get

      prq(3abc) - abc(3pqr) = 0

Approved