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If a+b+c=0=p+q+r then the value of determinant pa qb rc qc ra pb rb pc qa is? how
When we open the matrice we get
prq(a3 + b3 + c3) - abc(p3 + q3 +r3)
we have a+b+c = p+q+r =0
so a3+b3+c3 = 3abc and p3+r3+q3 = 3pqr
putting values in above equation we get
prq(3abc) - abc(3pqr) = 0
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