p takes these values ( p1,p2) at that time the equation p/2x=a/(x+c)+b/(x-c) will get general solution ....... so proof p1-p2=(ab)^1/4

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p takes these values ( p1,p2) at that time the equation p/2x=a/(x+c)+b/(x-c) will get general solution ....... so proof p1-p2=(ab)^1/4

p takes these values ( p1,p2) at that time the equation p/2x=a/(x+c)+b/(x-c) will get general solution ....... so proof p1-p2=(ab)^1/4

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p takes these values ( p1,p2) at that time the equation p/2x=a/(x+c)+b/(x-c) will get general solution ....... so proof p1-p2=(ab)^1/4

p takes these values ( p1,p2) at that time the equation p/2x=a/(x+c)+b/(x-c) will get general solution ....... so proof p1-p2=(ab)^1/4

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