# if  are the roots of the equation . Then what is the value of .

Sathya
35 Points
10 years ago

$\dpi{100} \bg_white I$ $\dpi{100} \bg_white am$  $\dpi{100} \bg_white getting$ $\dpi{100} \bg_white it$ $\dpi{100} \bg_white as$ $\dpi{100} \bg_white :$

$\dpi{100} \bg_white =$ $\dpi{100} \bg_white 1$ $\dpi{100} \bg_white +$

$\dpi{100} \bg_white \fn_cm Donno$ $\dpi{100} \bg_white \fn_phv whether$ $\dpi{100} \bg_white \fn_jvn it$ $\dpi{100} \bg_white \fn_cm is$ $\dpi{100} \bg_white \fn_cm wrong$ $\dpi{100} \bg_white \fn_cm or$ $\dpi{100} \bg_white \fn_cm right$   $\dpi{100} \bg_white \fn_cm :p$

Mir Noaman Ali IIT-Roorkee
57 Points
10 years ago

Dear Sathyaram

a (alpha) b (beta) a+b =1 so (a+b)^2012=1 now (a-b)^2=(a+b)^2-2ab=1-2=-1 so a-b whole square =-1 hence a-b=i (iota),(a-b)^2012=i^2012=1 so answer is 1+1=2 , Please Approve my answer if you have understood the solution

Regards

Noaman Ali

Swapnil Saxena
102 Points
10 years ago

the answer for the question is 1+(3)1006

Vaishal Shah
50 Points
10 years ago

1+3^1006