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if are the roots of the equation . Then what is the value of .
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Dear Sathyaram
a (alpha) b (beta) a+b =1 so (a+b)^2012=1 now (a-b)^2=(a+b)^2-2ab=1-2=-1 so a-b whole square =-1 hence a-b=i (iota),(a-b)^2012=i^2012=1 so answer is 1+1=2 , Please Approve my answer if you have understood the solution
Regards
Noaman Ali
the answer for the question is 1+(3)1006
1+3^1006
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