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5^x+1 + 5^1-x=26
(5)(5x) + (5)/(5x) = 26
5(5x + 1/(5x))=26
considering 5x = y the equation becomes
5y2 - 26y +5 = 0
or
y = 5 , 1/5
therefore x = 1 , -1
5x+1 + 51-x=26 (5)(5x) + (5)/(5x) = 26 5(5x + 1/(5x))=26 let m=5x 5m2 - 26m +5 = 0 5m2-25m-m+5=0 5m(m-5)-(m-5)=0 (5m-1)(m-5)=0 m= 5 , 1/5 thus x = 1 , -1.
5x+1 + 51-x=26
5m2 - 26m +5 = 0
5m2-25m-m+5=0
5m(m-5)-(m-5)=0
(5m-1)(m-5)=0
m= 5 , 1/5
thus x = 1 , -1.
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