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arg{sin8π/5+i(1+cos8π/5)} is equal to a) 3π/10 b) 7π/10 c) 4π/5 d) 3π/5

arg{sin8π/5+i(1+cos8π/5)} is equal to


a) 3π/10


b) 7π/10


c) 4π/5


d) 3π/5

Grade:

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
12 years ago

arg{sin8π/5+i(1+cos8π/5)}

=arg{2sin(4π/5)cos(4π/5)+i(2cos24π/5)}

=arg[2icos(4π/5){cos(4π/5)-isin(4π/5)}]

=arg{i}+arg{cos(4π/5)-isin(4π/5)}

 =∏/2 +(-4∏/5)

 =-3∏/10

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