The letters of the word ASSASSINATION are arranged at random. What is the probability of a getting NO TWO As are coming...???

ASSASSINATION can be arranged in 13!/(3!*4!*2!*2!) ways.

No two As coming together.

x  S  x  S  x  S  x  S  x  I  x  N  x  T  x  I  x  O  x  N x

A can be put in place of any x. (3 As can be put in 11 places in 11C3 ways).

No of favourable conditions = 10!/(4!*2!*2!) * 11C3

Probability = [10!/(4!*2!*2!) * 11C3]/[13!/(3!*4!*2!*2!)]

Your answer is great ..Thank u so much..I wont forget you valuable respobnse towards my question.!