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The letters of the word ASSASSINATION are arranged at random. What is the probability of a getting NO TWO As are coming...???
ASSASSINATION can be arranged in 13!/(3!*4!*2!*2!) ways.
No two As coming together.
x S x S x S x S x I x N x T x I x O x N x
A can be put in place of any x. (3 As can be put in 11 places in 11C3 ways).
No of favourable conditions = 10!/(4!*2!*2!) * 11C3
Probability = [10!/(4!*2!*2!) * 11C3]/[13!/(3!*4!*2!*2!)]
Your answer is great ..Thank u so much..I wont forget you valuable respobnse towards my question.!
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