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if p+q+r=16, b+c=4 and x,y,z are the solution of linear equations (x/p)+(y/p-b)+(z/p-c)=1 (x/q)+(y/q-b)+(z/q-c)=1 (x/r)+(y/r-b)+(z/r-c)=1 then x+y+z is

if p+q+r=16, b+c=4 and x,y,z are the solution of linear equations


(x/p)+(y/p-b)+(z/p-c)=1


(x/q)+(y/q-b)+(z/q-c)=1


(x/r)+(y/r-b)+(z/r-c)=1 then x+y+z is

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1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
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