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If a,b,cd are positive real numbers such that a+b+c+d=2,then M=(a+b)(c+d) saties fies the relation a)0 c)2

If a,b,cd are positive real numbers such that a+b+c+d=2,then M=(a+b)(c+d) saties fies the relation


a)0

c)2<=M<=3     d)none of these

Grade:12

1 Answers

Swapnil Saxena
102 Points
9 years ago

Maybe the correct answer to this question is 5/9 <= M <=1 , (Using AM-GM inequalities).

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