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Find the number of values of x(x is real) for which 641/x+481/x=801/x

sudarshan gupta , 15 Years ago
Grade Upto college level
anser 1 Answers
askIITiansexpert nagesh

Last Activity: 15 Years ago

 

Given, 641/x+481/x = 801/x

Let y= 1/x

Then the equation is 64y+48y = 80y

Divide by 16y on both sides, we get

3y + 4y = 5y

It is of form

sinyz + cosyz =1,    where sinz=3/5,cosz=4/5

now above equality is true iff y=2, Since sinz≠0,±1

→ x=1/2

hence number of solutions is 1.

 

 

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