askIITiansexpert nagesh
Last Activity: 15 Years ago
Given, 641/x+481/x = 801/x
Let y= 1/x
Then the equation is 64y+48y = 80y
Divide by 16y on both sides, we get
3y + 4y = 5y
It is of form
sinyz + cosyz =1, where sinz=3/5,cosz=4/5
now above equality is true iff y=2, Since sinz≠0,±1
→ x=1/2
hence number of solutions is 1.