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Statement 1: x + y + z = 5 and xy + yz + zx = 3, (x, y, z R) then the probability for x is positive only is 13/6. Statement 2: If x + y + z = 5 and xy + yz + zx = 3, then maximum and minimum value of x, y, z are same. dis 1s frm ur questions....

Statement 1: x + y + z = 5 and xy + yz + zx = 3, (x, y, z R) then the probability for x is positive only is 13/6.


Statement 2: If x + y + z = 5 and xy + yz + zx = 3, then maximum and minimum value of x, y, z are same.


dis 1s frm ur questions....

Grade:10

1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
8 years ago
Hello student,
Please find my response to your question below
Iam not able to interpret your query as in the first part you are saying the probability is 13/6 which is impossible.
In the second part we get maximum value as 13/3 and minimum value as -1

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