Swapnil Saxena
Last Activity: 12 Years ago
(0,1),(0,-1),(1,0),(-1,0) are the solutions of the equation.
becoz sin(x)+sin(y) = 2sin(x+y/2)cos(x-y/2)
and sin(x+y)= 2sin(x+y/2)cos(x+y/2)
putiing both of them equal
we get cos(x-y/2) = cos(x+y/2)
then (x-y)/2= (x+y)/2 or (x-y)/2=-(x+y)/2 as cos(x)=cos(-x)
x=0 or y=0
Put these value in mod(x)+mod(y)=1 and get possible values of x and y.