EQUATION

Question

CONSIDER THE EQUATION x^5 + x= 10. SHOW THAT THE EQUATION HAS ONLY ONE REAL ROOT; ALSO THAT THE ROOT LIES BETWEEN 1 AND 2; AND ALSO THAT THE ROOT MUST BE IRRATIONAL.

jitender lakhanpal · Accepted Answer

Dear Aritra,f(x)=x^5 + x - 10 = 0number of times the sign changes in the expression is 1 so it can have utmost 1 real rootand now put x = 1 we get f(1) = -8so <0and if we put x = 2 we get f(2) = 24 so >0so we see that there will be root between 1 and 2We are all IITians and here to help you in your IIT JEE preparation.Now you can winby answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar..jitender

Algebra> EQUATION...

CONSIDER THE EQUATION x^5 + x= 10. SHOW THAT THE EQUATION HAS ONLY ONE REAL ROOT; ALSO THAT THE ROOT LIES BETWEEN 1 AND 2; AND ALSO THAT THE ROOT MUST BE IRRATIONAL.

ARITRA SINHA , 12 Years ago

jitender lakhanpal

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Algebra> EQUATION...

CONSIDER THE EQUATION x^5 + x= 10. SHOW THAT THE EQUATION HAS ONLY ONE REAL ROOT; ALSO THAT THE ROOT LIES BETWEEN 1 AND 2; AND ALSO THAT THE ROOT MUST BE IRRATIONAL.

ARITRA SINHA , 12 Years ago

jitender lakhanpal

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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