#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# The product of the first three terms in geometric progression is 8000. If the first term is 4, find the second and third terms

## 1 Answers askiitiansexpert soumyajit_iitkanpur
8 Points
11 years ago

Hi,

Let the first three terms of the GP be 4, 4r, 4r^2 .

According to the problem,  4 x 4r x 4r^2 = 8000

(4r)^3 - (20)^3 = 0

(4r - 20) (16r^2 + 80r + 400) = 0

either 4r - 20 = 0      =>  r = 5

or,   16r^2 + 80r + 400 = 0             =>         r^2 + 5r + 25 = 0

r = (-5 ± i 5√3)/2

If imaginary value of r is considered then second and third term of the GP will be imaginary also. Hence product of first three terms will also be imaginary, which is not true. Hence acceptable soln is r = 5.

Therefore three terms are 4, 20, 100 .

## ASK QUESTION

Get your questions answered by the expert for free