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In how many ways can a lawn tennis mixed doubles be made up from seven married couples if no husband and wife play in the same set?
SELECT 2 PERSONS FROM 14
NO. OF WAYS = 14C2=91
IN THISTHERE ARE 7 WAYS IN WHICH HUSBAND WIFE COME TOGETHER
TOTAL WAYS= 91-7=84
OUT OF THESE 84 TEAMS WE HAVE TO SELECT 2 TEAMS
NO. OF WAYS = 84C2 = 3486 WAYS ANS
Thanks for replying. But the answer is 840 only. I think u misjudged the question. in first step u took 14C2 , in this case it is possible that we select 2 husbands but no wife... instead of this it must be like this
7C2 x 7C2 since we want two husbands but two wives also. these are 21 x 21 = 441 ways.
now we want to deduct the unfavorable cases i.e 14 cases i m stuck up at this point how to get the answer ahead?
can anyone help?
actually this question is given in permutation chapter can this be solved without combination ?
it should be 210.
as u select two husbands u will have five wives left to select from.......
a regular polygon of 9 sides each of length 2 unit is inscribed in a circle the radius of circle is
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