Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Find largest integer x for which another integer n exists with nx = n + 12x
Hi Abhishek,
Rearrange the given equation, and we have:
x(n-12) = n
Or x = n/(n-12).
Now we have to find the largest x --------- (So we will assume x to be positive, since if it is negative, then it cannot be the largest).
So x = n/(n-12).
So we have to maximise n/(n-12).
Now, x = n/(n-12) = 1 + 12/(n-12).
This will clearly be maximum when (n-12) = 1..... ie n = 13.
So the maximum value of x will be 13.
Hope this helps.
Wish you all the best.
Regards,
Ashwin (IIT Madras).
I thought the maximum value for it will be 12 because:
As x = n/(n-12)
When n=12, x=12/0=Infinity.......
Thus it should be 12 na?
Satyaram,
No n cant be 12.
Put n=12 in the original eqn,
You will get 12x = 12+12x....
Which is absurd.
Hence x = 13, fon n=13.
Ashwin (IIT MadraS).
But wats wrong in it dude?
nx = n + 12x
Or x = n/(n-12)
Substitute n=12,
12/12-12=12/0 = Infinity=x....
Substitute n=13,
13/13-12=13/1=13=x
Since Infinity is greater than 13,
Y,The Largest value for x should not be 13?......
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !