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# A and B are 2 sets n(A-B)=32+x , n(B-A)=5x and n(AnB)=x. how to calculate x value

jitender lakhanpal
62 Points
10 years ago

Dear Thamizsh,

there is a information missing of that of n(AUB)  because without tihs value we can not find the value of x

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thamizh arasi
4 Points
10 years ago

but in maths book they gave the x value, thats why i asked the solution

Sri Rangan
18 Points
7 years ago
solution
given:
n(A-B)=32+x
n(B-A)= 5x
n(AUB) = x
n(A) = n(B)

n(A)= n(A-B) + n(AnB) (formula)
n(A) = 32+X+X
n(A) = 32+X,
n(B)= n(B-A)+n(AnB) (formula)
n(B) = 5X+X
n(B) = 6X.
n(A)=n(B) (given)
32+2X= 6X
32+2X-6X=0
32-4X=0
-4X=-32
X=32/4
X=8