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If a,b,c are in AP such that a+b+c=0,then roots of the equation px2+qx+b=0;(pq≠0) are
a.real and identical
b.real and distinct
c.imaginary
d.none of these
Hi Menka,
Now a,b,c are in AP. So 2b=a+c
a+b+c = 0, will give 3b=0 or b=0.
Hence the QE becomes, px^2 + qx = 0.
Hence one root is 0, and the other is -q/p.
Since pq is not zero, the value -q/p can never be 0.
Hence real and distinct roots. Option (B).
Hope it helps.
Best Regards,
Ashwin (IIT Madras).
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