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If a,b,c are in GP and a+b,b+c,c+a are in AP,then
a)b-2a=-c
b)b+3c=-2a
c)3c-b=2a
d)c+b=2a
common difference, d,
(b+c)-(a+b) = (c+a)-(b+c) = d
=> b+c-a-b = c+a-b-c
=> c-a = a-b
=> b-2a = -c
Thus it is the first option(a).
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