the middle term expansion of (x^2+1/x^2+2)^n

Dear Parul,

(x^2 +1/x^2 +2)^n=(x+(1/x))²ⁿ

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Askiitians Experts

CHETAN MANDAYAM NAYAKAR

Hi Parul,

x²+1/x²+2 = (x+1/x)²

So the given expression is (x+1/x)²ⁿ.

And the middle term would be ²ⁿC_nxⁿ(1/x)ⁿ = ²ⁿC_n.

Hope this helps.

Best Regards,

Ashwin (IIT Madras).