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the middle term expansion of (x^2+1/x^2+2)^n

the middle term expansion of (x^2+1/x^2+2)^n

Grade:11

2 Answers

Chetan Mandayam Nayakar
312 Points
9 years ago

Dear Parul,

(x^2 +1/x^2 +2)^n=(x+(1/x))2n

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CHETAN MANDAYAM NAYAKAR

Ashwin Muralidharan IIT Madras
290 Points
9 years ago

Hi Parul,

 

x2+1/x2+2 = (x+1/x)2

 

So the given expression is (x+1/x)2n.

And the middle term would be 2nCnxn(1/x)n = 2nCn.

 

Hope this helps.

 

Best Regards,

Ashwin (IIT Madras).

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