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Dear rupali,
the roots will be real and distinct
the solution is attached
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jitender
Hi Rupali,
The discriminant of the QE is,
D = 25b2 - 12ac = 25(-a-c)2 - 12ac = 25a2+25c2+50ac-12ac = 25a2+25c2+38ac
= 6a2+6b2+19a2+19c2+38ac = 6a2+6b2+19(a+c)2 -------- (which is always poitive, as they are square terms)
As D > 0, the roots of this QE are always real and distinct.
Hope that helps.
All the best.
Regards,
Ashwin (IIT Madras).
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