Jitender Singh
Last Activity: 10 Years ago
Ans:
Hello Student,
Please find answer to your question below
The roots of the equation f(x) = 0 are non-real complex.
So f(x) will not touch the real axis. Either it is above or below the real axis.
Given the condition
a + c < b
which can be interpreted as
f(-1) < 0
a -b + c < 0
a + c < b
So f(x) is -ve for x = -1. So it will be -ve for all x.
f(-2) < 0
4a – 2b + c < 0
4a + c < 2b 
