Flag Algebra> quadratic eqn...
question mark

The roots of ax2+bx+c=0, where a≠0. an coefficents are real,are non-real complex and a+c

1) 4a+c>2b

2) 4a+c<2b

3)4a+c=2b

4) none

pooja sarkar , 14 Years ago
Grade 12
anser 1 Answers
Jitender Singh
Ans:
Hello Student,
Please find answer to your question below

f(x) = ax^2 + bx + c
The roots of the equation f(x) = 0 are non-real complex.
So f(x) will not touch the real axis. Either it is above or below the real axis.
Given the condition
a + c < b
which can be interpreted as
f(-1) = a-b+c
f(-1) < 0
a -b + c < 0
a + c < b
So f(x) is -ve for x = -1. So it will be -ve for all x.
f(-2) = 4a-2b+c
f(-2) < 0
4a – 2b + c < 0
4a + c < 2b
Last Activity: 11 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments