IF A1,A2,A3,...,A BE N-TH ROOTS OF THE UNITY THEN THE VALUE OF (A1/3-A1+A2/3-A2+A3/3-A3+...+A/3-A)=

A)N/3^N-1

B)N-1/3^N-1

Hello student,
Please find the answer to your question below
GivenA1,A2,A3,...,ABE N-TH ROOTS OF THE UNITY
Then(A1/3-A1+A2/3-A2+A3/3-A3+...+A/3-A)=
taking 1/3 common from above we get
(A1+A2+......+An)/3-(A1+A2+......+An)=0
because according to the properties of nth roots of unity
Sum of nth roots of unity is zero.