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A number when successively divided by 9, 11 and 13 leaves remainders 8, 9 and 8 respectively.Finf the number.


A number when successively divided by 9, 11 and 13 leaves remainders 8, 9 and 8 respectively.Finf the number.


Grade:10

2 Answers

Ashwin Muralidharan IIT Madras
290 Points
9 years ago

Hi Sathyaram,

 

First when the number is divided by 9. the remainder is 8.

So N = 9x+8.

Similarly, next x = 11y+9, and y=13z+8.

So N = 99y+89 = 99(13z+8)+89 = 1287z+792+89 = 1287z+881.

So N is of the form, 1287*(A whole Number)+881.

 

If you need to find the minimum number, then it would be 881.

 

Hope that helps.

 

All the best.

Regards,

Ashwin (IIT Madras).

Sathya
35 Points
9 years ago

Thanks for your reply.It was very helpful! Smile

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