A number when successively divided by 9, 11 and 13 leaves remainders 8, 9 and 8 respectively.Finf the number.

Hi Sathyaram,

First when the number is divided by 9. the remainder is 8.

So N = 9x+8.

Similarly, next x = 11y+9, and y=13z+8.

So N = 99y+89 = 99(13z+8)+89 = 1287z+792+89 = 1287z+881.

So N is of the form, 1287*(A whole Number)+881.

If you need to find the minimum number, then it would be 881.

Hope that helps.

All the best.

Regards,

Ashwin (IIT Madras).

Thanks for your reply.It was very helpful!