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A number when successively divided by 9, 11 and 13 leaves remainders 8, 9 and 8 respectively.Finf the number.
Hi Sathyaram,
First when the number is divided by 9. the remainder is 8.
So N = 9x+8.
Similarly, next x = 11y+9, and y=13z+8.
So N = 99y+89 = 99(13z+8)+89 = 1287z+792+89 = 1287z+881.
So N is of the form, 1287*(A whole Number)+881.
If you need to find the minimum number, then it would be 881.
Hope that helps.
All the best.
Regards,
Ashwin (IIT Madras).
Thanks for your reply.It was very helpful!
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