Ashwin Muralidharan IIT Madras
Last Activity: 13 Years ago
Hi Himanshu,
Take a common and you have a{C0 - C1 + C2 -.......} -------------- (1)
Take -b common and you have -b{C1 - 2C2 + 3C3 -........} ------------- (2)
In the expansion of (1-x)^n, put x=1, you will get (1) = 0
And for the terms in bracket of (2), differentiate (1-x)^n, and put x=1
ie put x=1 in -n*(1-x)^n-1, which is again 0.
And hence the answer is 0.
Best Regards,
Ashwin (IIT Madras).