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How to calc. value of (25.364*61.65)/.091 using log tables? Explain in detail.
logs are to the base 10 ,as 25.364 is between 10^1 to 10^2 1.-----. then find the log for 0.2536 since log can be used only for 4 nos.
61.65 is between 10^1 to 10^2 1.-----. then find the log for 0.6165. thereafter add both their logs
log(a*b)=log a+log b
(1.4031+10)+(1.7896+4)
=1.4041+1.7900
=3.1941
and find the antilog of 3.1941
3194
antilog=0.1563 ,as 3 was present
0.1563*10*10*10*10=1563
now you want 1563/0.91
1563 betw 10^3 & 10^4
log is 3.1941
write 0.091 =0.91/10
mutiply 10in the numerator
4.1941-0.9590=3.2351
antilog=2351's antilog=0.1718*10*10*10*10*10*10
your ans is approx 17180
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