roots of quation log 2 (n 2 -4n+5)=n-2 are

Question

Jitender Singh · Answer

Ans:
Hello Student,
Please find answer to your question below

$log_{2}(n^{2}-4n+5) = n-2$
$f(n) = n^{2}-4n+5$
is always +ve for all values of n. So domain is OK.
Now, if we draw the graph
$f_{1}(n) = log_{2}(n^{2}-4n+5)$
For n = 2, it touches the x – axis.
And for
$f_{2}(n) = n-2$
For n = 2, it touche the x – axis.
From the grapg it is clear that n = 2 is the solution.

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roots of quation log 2 (n 2 -4n+5)=n-2 are

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roots of quation log₂(n²-4n+5)=n-2 are