The number of solutions of the equation (1-2(log x2)2)/(log x-2 (logx )2) = 1

Dear Kshitiz,

let logx=y, equation becomes (1-8y²)=y-2y²

6y²+y-1=0,y=(-1±5)/2=-3 or +2

log(x)=-3 or 2,x=e^-3 or e²

Thus, there are two solutions

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