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The number of solutions of the equation (1-2(log x2)2)/(log x-2 (logx )2) = 1
Dear Kshitiz,
let logx=y, equation becomes (1-8y2)=y-2y2
6y2+y-1=0,y=(-1±5)/2=-3 or +2
log(x)=-3 or 2,x=e-3 or e2
Thus, there are two solutions
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Askiitians Experts
Chetan Mandayam Nayakar
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