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The number of different words that can be formed with the word TRIANGLE so that no two vowels are together is : (a)7200 (b)36000 (c)14400 (d)1240

The number of different words that can be formed with the word TRIANGLE so that no two vowels are together is :
(a)7200 (b)36000 (c)14400 (d)1240

Grade:12

4 Answers

Chetan Mandayam Nayakar
312 Points
9 years ago

Answer= 3*2*1*5*4*(6*5*4/((3^2)(3^2)))

Attention Dear Moderator:The reason why this solution is presented so messy is that I am using Windows 7 ultimate and none of the formatting tools above (bold,italics, subscript, superscript,etc.) work. However, there is no problem with Windows XP

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govind redddy
18 Points
9 years ago

Option C  i.e. 14400 because there are eight letters in the word TRIANGLE in which TRNGL are consonants and IAE are the vowels there are  six places in which the the vowels can be placed in 6P3 ways and the consonants can be arranged in 5! ways so the total is 6P3 multiplied by 5! sothe answer is 14400.

jareen samoht
8 Points
6 years ago
it is 36000
Umang goyal
23 Points
3 years ago
By gap methodThere are 5 consonant and 3vowels there are 6c3 ways of selecting vowels.they can arrange in 3! Also consonant In 5! WaysSo total ways 6c3×3!×5!=14400

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