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Find the sum of all numbers that can be formed with the digits 2,3,4,5 taken all at a time.
Sum = 3![(2+3+4+5) + (20+30+40+50) + (200+300+400+500) + (2000+3000+4000+5000)] This is because any four-digit number abcd can be written as (1000a + 100b+ 10c + d)....................And as can be seen, each of 2,3,4 and 5 occur exactly 3! times for a particular place value.............
Sum = 3![(2+3+4+5) + (20+30+40+50) + (200+300+400+500) + (2000+3000+4000+5000)]
This is because any four-digit number abcd can be written as (1000a + 100b+ 10c + d)....................And as can be seen, each of 2,3,4 and 5 occur exactly 3! times for a particular place value.............
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