sanatan sharma
Last Activity: 13 Years ago
x=(a-b)/a,
a(a+b)(a-b)2/a2 -(b(a-b)(a-b)/a)=(a-b)2
=((a-b)/a)=(a-b)2
=((a-b)/a)(a2-b2+b2-ab)=(a-b)2
=a(a-b)(a-b)/a =(a-b)2
α+β=[-(-b(a-b))]/[a(a+b)]
(a-b)/a +β = [b(a-b)]/[a(a+b)]
β = (a-b)[{b/a(a+b)} - 1/a]
therefore β = (b-a)/(b+a)