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the sum of max and min values of function f(x)=sin -1 2x+cos -1 2x+sec -1 2x is a) π b) π/2 c) 2 π d) 3 π/ 2

11 years ago

Answers : (3)

AskIITian Expert Priyasheel - IITD
8 Points


11 years ago chandra sekhar
10 Points

Hi Anurag,


sin-12x+cos-12x = π/2 for all x

sec-12x belongs to [0,π ]-{π/2}

therefore min of
sec-12x is 0

                   max of sec-12x is π

therefore min of f(x) is

                   max of f(x) is 3π/2

sum of min and max  values of f(x) is (
π/2 + 3π/2) = 2π

Ans: (c)

All the best chandra sekhar

11 years ago
askIITianexpert IITDelhi
8 Points

As Sin-1x  & Cos-1x is defined for x belongs to[-1,1] . Sec-1x is defined for x≤-1 & x≥1.Also Sin-1x+Cos-1x=¶/2 in the domain specified.

Domain of above function f(x) is x={-1/2 , 1/2}   (By solving inequalities -1≤x≤1,x≤-1 & x≥1)

Hence max{f(x)}=¶/2+Sec-1 (2*1/2)=¶/2+¶/2=¶

while min{f(x)}=0.So their sum=¶       ;   Answer is (a).


11 years ago
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