#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Sum of binomial co-efficients of (1+x+x^2)^n = 3^n. (As given in the book)But if I expand (1+x+x^2)^n = [1+x(1+x)]^n and then put x = 1, am not getting 3^n. Somebody help.

Godfrey Classic Prince
633 Points
9 years ago

Dear Palash Chatterjee,

Look ....by putting x=1 in [1+x(1+x)]n we really get 3n which is the answer required !!

It is [1+1(1+1)]n when we put x=1

=[1+2]n

=3n

All the Best & Good Luck !!

Please approve my answer if you liked it by clicking on "Yes" given below...!!

SAGAR SINGH - IIT DELHI
879 Points
9 years ago

Dear student,

You are making error in bracket term while taking common...

BEST OF LUCK..!!!!

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Sagar Singh - IIT Delhi

Palash Chatterjee
14 Points
9 years ago

I was actually making a mistake while expanding the equation (I messed up the co-efficients). Anyway, thanks a lot for y our help.