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f(x)=2x^n+a, if f(2)=26 and f(4)=138, then f(3)is equal to
Easy man..64…look
2.(2)^n+a=26
And 2(4)^n+a=138…solve to get a=10 and n=3….hencef(3)=2(3)^3+10=64
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