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Given that the equation z 2 +(p+iq)z+r+is=0,where p,q,r,s are real and non-zero root then 1. pqr=r 2 +p 2 s 2. prs=q 2 +r 2 p 3. qrs=p 2 +s 2 q 4. pqs=s 2 +q 2 r


Given that the equation z2+(p+iq)z+r+is=0,where p,q,r,s are real and non-zero root then


1.  pqr=r2+p2s

2.  prs=q2+r2p

3.  qrs=p2+s2q





4.  pqs=s2+q2r




Grade:12th Pass

1 Answers

Aman Bansal
592 Points
10 years ago

Dear Pankaj,

Ans is 4.

Assume  x be a real root.

put x into the eqn and separate real and imaginary parts  to get:

x^2+px+r=0 and qx+s=0.

put x=-s/q in first one to get option 4.

Best Of luck

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