Given that the equation z2+(p+iq)z+r+is=0,where p,q,r,s are real and non-zero root then1.pqr=r2+p2s2.prs=q2+r2p3.qrs=p2+s2q4.pqs=s2+q2r

Dear Pankaj,

Ans is 4.

Assume  x be a real root.

put x into the eqn and separate real and imaginary parts  to get:

x^2+px+r=0 and qx+s=0.

put x=-s/q in first one to get option 4.

Best Of luck

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