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Given that the equation z 2 +(p+iq)z+r+is=0,where p,q,r,s are real and non-zero root then 1. pqr=r 2 +p 2 s 2. prs=q 2 +r 2 p 3. qrs=p 2 +s 2 q 4. pqs=s 2 +q 2 r

 


Given that the equation z2+(p+iq)z+r+is=0,where p,q,r,s are real and non-zero root then



 


1.  pqr=r2+p2s



2.  prs=q2+r2p


3.  qrs=p2+s2q



 



 



 


 

4.  pqs=s2+q2r



 


 


 

Grade:12th Pass

1 Answers

Aman Bansal
592 Points
9 years ago

Dear Pankaj,

Ans is 4.

Assume  x be a real root.

put x into the eqn and separate real and imaginary parts  to get:

x^2+px+r=0 and qx+s=0.

put x=-s/q in first one to get option 4.

Best Of luck

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