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The incentre of the triangle with vertices (1,√3 ), (0, 0) and (2, 0) is : (A) (1,√3/2) (B) (2/3,1/√3) (C) (2/3,√3/2) (D) (1,1/√3)
since the given triangle is equilateral , its incentre is same as centroid I(x,y) = (1+0+2 / 3 , 1.732 + 0 +0 /3) = ( 1 , 1/31/2) option D -- regards Ramesh
since the given triangle is equilateral ,
its incentre is same as centroid
I(x,y) = (1+0+2 / 3 , 1.732 + 0 +0 /3)
= ( 1 , 1/31/2)
option D
--
regards
Ramesh
We know that the given triangle is equilateral triangle therefore its incenter and its centroid should be the same the applying the formula of the centroid we get that the coordinates of the incenter are (1,1/3^(1÷2))
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