The incentre of the triangle with vertices (1,√3 ), (0, 0) and (2, 0) is :
(A) (1,√3/2) (B) (2/3,1/√3)
(C) (2/3,√3/2) (D) (1,1/√3)

Question

The incentre of the triangle with vertices (1,&radic;3 ), (0, 0) and (2, 0) is : (A) (1,&radic;3/2) (B) (2/3,1/&radic;3) (C) (2/3,&radic;3/2) (D) (1,1/&radic;3)

Ramesh V · Answer

since the given triangle is equilateral , its incentre is same as centroid I(x,y) = (1+0+2 / 3 , 1.732 + 0 +0 /3) = ( 1 , 1/3 1/2 ) option D -- regards Ramesh

Ashwin Sheoran · Answer

We know that the given triangle is equilateral triangle therefore its incenter and its centroid should be the same the applying the formula of the centroid we get that the coordinates of the incenter are (1,1/3^(1÷2))

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The incentre of the triangle with vertices (1,√3 ), (0, 0) and (2, 0) is : (A) (1,√3/2) (B) (2/3,1/√3) (C) (2/3,√3/2) (D) (1,1/√3)

The incentre of the triangle with vertices (1,√3 ), (0, 0) and (2, 0) is :
(A) (1,√3/2) (B) (2/3,1/√3)
(C) (2/3,√3/2) (D) (1,1/√3)

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