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Grade: 12


A pole stands vertically inside a triangular park Δ ABC. If the angle of elevation of the top of the pole from each corner of the park is same, then in Δ ABC the foot of the pole is at the : (A) centroid (B) circumcentre (C) incentre (D) orthocenter.

11 years ago

Answers : (3)

Pavan kumar
18 Points

(D) orthocentre

OD is the vertical pole.

Hence <DOA = <DOB = 90

 It is given that <OAD = <OBD

OD is common to both triangle AOD and BOD

Hence triangles AOD and BOD are congruent.

Therefore OA = OB.

Similarly, OA = OC.

Therefore o is equidistant from A,B and C, and hence is at the orthocentre.


11 years ago
Ramesh V
70 Points

since the angle of elevation of pole is same, which means for a particular height of pole, the distance of pole feet from and any point A,B,C is same

This means that the feet of pole shld be at centroid of triangle ABC




11 years ago
AskIITian Expert Priyasheel - IITD
8 Points


11 years ago
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