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If a and β (α 2 + bx + c = 0 , where c (A) 0 (C) α
let α, β be roots , α + β = -b and α*β = c as c<o and b>0 i.e., -b<0 α.β < 0 and α+β<0 so both α , β must be negative . as α < β , so the answer is : 0 < α < β -- regards Ramesh
let α, β be roots ,
α + β = -b and α*β = c
as c<o and b>0 i.e., -b<0
α.β < 0 and α+β<0
so both α , β must be negative .
as α < β , so the answer is : 0 < α < β
--
regards
Ramesh
Option b is right. Let the roots be p and q. We have p+q<0 and pq<0. This means p<0 and q>0. p+q<0 means q<-p = |p| Hence we have p<0<q<|p|
Option b is right.
Let the roots be p and q. We have p+q<0 and pq<0. This means p<0 and q>0. p+q<0 means q<-p = |p|
Hence we have p<0<q<|p|
we have Alpha + beta = -b ; alpha*beta = c As c<0 and b>0 ,we get alpha<0<beta also Beta = -beta - alpha < - alpha = |Alpha| thus alpha < 0 < beta < |Alpha| therefore B is the right option
we have Alpha + beta = -b ; alpha*beta = c
As c<0 and b>0 ,we get alpha<0<beta
also Beta = -beta - alpha < - alpha = |Alpha|
thus alpha < 0 < beta < |Alpha|
therefore B is the right option
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